A ball is thrown vertically upward with a velocity of 20 m per second calculate the maximum height attained by the ball
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First take g=9.8m/s
v=20m/s
u=0
Therefore, apply the formula:
v^2=u^2 +2gs [s is the height]
(20)^2=0 + (2*9.8*s)
400= 0 + 19.6s
-19.6s= 0-400
s=-400/-19.6
s=20.4082=20.3
Therefore the maximum height attained by the ball is 20.3 metre.
v=20m/s
u=0
Therefore, apply the formula:
v^2=u^2 +2gs [s is the height]
(20)^2=0 + (2*9.8*s)
400= 0 + 19.6s
-19.6s= 0-400
s=-400/-19.6
s=20.4082=20.3
Therefore the maximum height attained by the ball is 20.3 metre.
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