Question

a ball is thrown vertically upward with a velocity of 40 m/s find (I) velocity after 4 s. (II) the height gain after 2 s. (III) the maximum height.

Answer 1

Answer:

I)0m/s

II)60m

III)80m

Explanation:

I)v=u-gt

v=40-(10*4)

V=0m/s

II)s=ut-1/2gt^2

s=40*2-1/2*10*2^2

s=80-20

s=60m

III)H max =u^2/2g

=40^2/2*10

=1600/20

=80m

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