Question

A ball is thrown vertically upward with a velocity of 48m/s .Find the maximum height to which it rises.

Answer 1

assuming the acceleration due to gravity is 10m/s raised to 2

${v}^{2} - {u }^{2} = 2as \\ 0 - {48}^{2} = 2 \times 10 \times s \\ 48 \times 48 \div 2 \times 10 = s \\ = 115.2m$