Physics, asked by pakiza95, 1 year ago

A ball is thrown vertically upward with a velocity of 98 m/s how high does the ball rise

Answers

Answered by goyalsushma446
3

V^2=u^2+2gs

V=98

U=0

g=-10

S=?

98×98 =0+2×10s

98×98=20s

98×98/20=s

S=480.2 m

Answered by janvi6488
3
let ,
u=0
v=98m/sec
g=-9.8m/sec^2
v^2=u^2+2gs
(98)^2=0^2+2×(-9.8)×s
9604 =19.6s
s= 9604/19.6
490m
Hence, ball rise upto 490m.
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