A ball is thrown vertically upward with a velocity of 98 m/s how high does the ball rise
Answers
Answered by
3
V^2=u^2+2gs
V=98
U=0
g=-10
S=?
98×98 =0+2×10s
98×98=20s
98×98/20=s
S=480.2 m
Answered by
3
let ,
u=0
v=98m/sec
g=-9.8m/sec^2
v^2=u^2+2gs
(98)^2=0^2+2×(-9.8)×s
9604 =19.6s
s= 9604/19.6
490m
Hence, ball rise upto 490m.
u=0
v=98m/sec
g=-9.8m/sec^2
v^2=u^2+2gs
(98)^2=0^2+2×(-9.8)×s
9604 =19.6s
s= 9604/19.6
490m
Hence, ball rise upto 490m.
Similar questions
Biology,
6 months ago
Computer Science,
6 months ago
Social Sciences,
6 months ago
English,
1 year ago
Physics,
1 year ago
CBSE BOARD X,
1 year ago
Hindi,
1 year ago
Math,
1 year ago