A ball is thrown vertically upward with an initial velocity of 96 feet per second. The distances (in feet) of the ball from the ground after t seconds is s(t) = 96t - 16t^2.
a. At what time t will the ball strike the ground?
b. From what time t is the ball more than 128 feet above the ground?
Pls. answer ASAP with correct solution/s.
Thank you in advance!
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Answer:
a) time=31.9 seconds,
b)more than 128 feet means time=3 minutes 44 seconds
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