Question

A ball is thrown vertically upward with avelocity of 19.6 m/s. The max height it attains is (g=9.8)​

Answer 1

trick .... H =u²/2g

( 19.6)²/2×9.8

19.6×19.6/9.8×2

= 19.6m is max height ...

hope it help you ..

Answer 2

$\huge\underline\mathfrak\green{Solution}$

H = u²/2g

= (19.6)²/ 2 × 9.8

Therefore the maximum height is 19.6m

Thanks!! ✨❤