Question

a ball is thrown vertically upward with initial velocity of 20m/s what is its maximum speed of ball in half way?(take g=10m/s^2

Answer 1

hope it helps.......☺☺☺☺

Answer 2

Thank you for asking this question. Here is your answer:

This is given:

u = 20m/s

v = 0 m/s

g = 9.8m/s2

Solution:

First you will use this formula: v=u−gt

0 = 20m/s−(9.8)(t)  

9.8t = 20

t = 2.04 seconds

Then you will use this formula: v2=u2−2gx

0=(20)2−2(9.8)(x)  

19.6x=400

x = 400/19.6

= 20.40 m

So the final answer is that the ball reaches the maximum height of around 20.40 m in 2.04 seconds.

If there is any confusion please leave a comment below.