Question

A ball is thrown vertically upwards and rises to a height of 19.6 m. What is the initial velocity of the ball? (take g = 9.8 m/s2)

Answer 1

Answer- Let initial velocity = u

Distance= s= 19.6 m

Final velocity= v

Acceleration due to gravity= g=a= 9.8 m/s²

v= 0 m/s (Whenever an object is thrown vertically upwards, its final velocity becomes 0 m/s as the ball comes to rest at that point)

We need to find u.

By using 3rd equation of motion, 2as= v² - u²

2 × 9.8 × 19.6= (0)² - (u)²

384.16= 0- u²

√384.16 = u

19.6 m/s = u

Therefore, initial velocity= 19.6 m/s

Please mark as the BRAINLIEST answer if helpful.

Answer 2

${\huge {\mathfrak {\pink {Answer :-}}}}$

Let the initial velocity of the ball be u.

It's final velocity will be zero as it stops after sometime in the air.

Now, g = 9.8 m/s.

So, v^2 = u^2 - 2gh

Or, (0)^2 = u^2 - 2 * 9.8 * 19.6

Or, 0 = u^2 - 19.6 * 19.6

Or, u^2 = 19.6 * 19.6

Or, u = 19.6

➡️ Therefore, initial velocity of the ball was 19.6 m/s.

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