Question

A ball is thrown vertically upwards from ground and a student gazing out of window sees it moving upward past him at 5 m/s. The window is 10 m above the ground.Find the maximum height of the ball.

Answer 1

v2−u2=2asv2−u2=2asu=?v=5m/ss=10ma=−10u=?v=5m/ss=10ma=−10Therefore 52−u2=2×(−10)×1052−u2=2×(−10)×10u2=225m/su2=225m/sMaximumheight=h=u22gMaximumheight=h=u22g=11.25m