Question

A ball is thrown vertically upwards from the ground. It crosses a point at the height of 25 m twice at an interval of
4s. The ball was thrown with the velocity of
(1) 20 m/s
(2) 25 m/s
(3) 30 m/s
(4) 35 m/s​

Answer 1

Answer:

After reaching the maximum height , it falls for 2seconds to reach the 25 m height.

Distance it has fallen is h = 0.5 gt^2 = 0.5*10* 4 =20 m.

Maximum height is 25+20 = 45 m.

Velocity at the bottom or the initial velocity is found from

u^2 = 2gh = 2*10*45 =900

u = 30 m/s.

Explanation:

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Answer 2

Answer:

C) 30 m/s

Explanation: