Question

A ball is thrown vertically upwards from the top of a tower with an initial velocity of 19.6 metre six in the ball reaches the ground after 5 seconds calculate first the height of Tower second the velocity of ball hitting the ground is equal to 9.8 metre per second square​

Answer 1

1. The height of the tower is 24.5 m.

2. The velocity of the ball on reaching the ground is 29.4 m/s.

Explanation:

Given:

Initial velovity of ball 'u' = 19.6 m/s

Time taken by ball to reach ground 't' = 5 sec.

Gravity 'g' = 9.8 m/s

Solution:

we know that,

⇒ g = v/t

⇒ t = v/g

=19.6/9.8

So, ⇒ t = 2 sec.

it means time taken to reach max. height is 2 seconds.

It means 2 seconds are taken by the ball to reach back to tower and rest of 1 second to reach to ground.

it means first two seconds are taken to make final velocity 'v' is zero (max. height).

⇒ v = 0 m/s

Time taken is 1 second to calculate height of tower (written above).

So, using equation of motion,

⇒ s = ut +1/2at^2

⇒ s = 19.6 x 1 +1/2 x 9.8 x 1

⇒ s = 24.5 m

From zero initial velocity at time 2 seconds to ground where time is 5 seconds. Now, time taken is 3 seconds from max. height to ground.

now, ⇒ v = u + at

⇒ v = 0 + 9.8 x 3

⇒ v = 29.4 m/s

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Answer 2

Answer:

Explanation:

1.  The height of the tower is 24.5 m.

2.  The velocity of the ball on reaching the ground is 29.4 m/s.

Explanation:

Given:

          Initial velovity of ball 'u' = 19.6 m/s

          Time taken by ball to reach ground 't' = 5 sec.

          Gravity 'g' = 9.8 m/s

Solution:

          we know that,

                                   ⇒ g =  

                                   ⇒   t =

                                          =

So,                               ⇒   t = 2 sec.

it means time taken to reach max. height is 2 seconds.

It means 2 seconds are taken by the ball to reach back to tower and rest of 1 second to reach to ground.

it means first two seconds are taken to make final velocity 'v' is zero (max. height).

                                   ⇒ v = 0 m/s

Time taken is 1 second to calculate height of tower (written above).

So, using equation of motion,

                                   ⇒

                                   ⇒ s = 19.6 x 1 + x 9.8 x

                                   ⇒ s = 24.5 m

From zero initial velocity at time 2 seconds to ground where time is 5 seconds. Now, time taken is 3 seconds from max. height to ground.

                                         

now,                             ⇒ v = u + at

                                    ⇒ v = 0 + 9.8 x 3

                                    ⇒ v = 29.4 m/s

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