Question

A ball is thrown vertically upwards from the top of the tower with speed hundred metre per second it strikes the pond near the base of the tower after 25 second the height of the Tower is​

Answer 1

Answer:

After 25 seconds, the height is 625 meter.

Explanation:

We can use the equations of motion to determine the height.

$-s= ut-\frac{1}{2}gt^2$

The final position lie below the initial position so ‘s’ is in negative form here.

U = 100 m/s and t = 25 second and g = 10 $m/s^2$

$-s=\left(100\times25\right)-\left(\frac{1}{2}\times 10\times25^2\right)$

$-s=2500-3125$

$-s=-625$

$s=625 \ m$