A ball is thrown vertically upwards. It returns
6 s later. Calculate : (i) the greatest height
reached by the ball, and (ii) the initial velocity
of the ball. (Take g = 10 m s2)
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Answer:
u = 30 m/s & s = 45 m
Explanation:
u = v - g t
0 = u - 10 x 3
0 = u - 30
u = 30 m/s
s = ut + 1/2 at^2
s = 30 x 3 + 1/2 x -10 x 9
s = 90 - 45
s = 45 m
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