Question

A ball is thrown vertically upwards. The velocity at one third of the maximum height is 8m/s. The velocity with chicj the ball was thrown is

Answer 1

Let the velocity with the ball is thrown upwards be v m/s.

Then the maximum height achieved => H = v^2/2g

Now it is given that,

at one-third of max. height v = 8 m/s.

H/3 =64/2*g

H =32*3/g => 9.6 m

v = > root(2gH) => root(2*10*9.6) => root(192) => 13.85 m/s

Hope this will help u... :-)