A ball is thrown vertically upwards with a speed of 10 metre per second from the top of a tower 200 height and other is thrown vertically downwards with the same speed simultaneously. the time difference between them and reaching ground in seconds if gravity is taken as 10 metre per second square
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Explanation:
The equation for an object’s height is h(t)=g/2 t² + vt + c, where h(t)=objects height at t seconds, g is gravity, v is initial velocity, and c is initial height. So, for the first ball, it hits the ground when h(t)=0. So:
0=g/2 t²+10 t +200
For the second ball, we have:
0=g/2 t²-10t+200
Solving for t in both equations, we get:
0=-4.9t²+10t+200
4.9t²-10t-200=0
t=7.5
and
0=-4.9t²-10t+200
4.9t²+10t-200=0
t=5.5
The difference is 7.5–5.5=2 secs
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