Question

A particle has a displacement of 24m towards east and 10m towards north and then 6m vertically upward. Find the magnitude of the sum of these displacement.

Answer 1

Answer:

26.68 m

Explanation:

Let unit vectors along

• East = i
• North = j
• Vertically upwards = k

Then,

Displacement of particle can be written as

D = 24i + 10j + 6k

Magnitude of displacement is then

|D| = √(24² + 10² + 6²) m = 26.68 m