Question

A ball is thrown vertically upwards with a speed of 30 metre second -1 it returns back to the hands of the thrower after 6 seconds calculate the maximum height attained by the ball (use g = 10ms^-2​

Answer 1

Answer:

45 meters

Explanation:

$when \: a \: body \: is \: thrown \: vertically \: up \\ given \: u \: = 30m {s}^{ - 1} \\ \: \: \: \: \: \:\: \: \: \: \: \: g \: = 10m {s}^{ - 2} \\ maximum \: height \: = \frac{{u}^{2}}{2g} \\ h \: = \frac{30 \times 30}{2 \times 10} \\ h = 45m$

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