A ball is thrown vertically upwards with a speed of 49m/s.Calculate 1.Maximum height of the ball 2.Total time taken by the ball to reach the earth's surface
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Answer:
122.5 m
10 second
Explanation:
At the highest point, velocity = 0.
Initial velocity = u
Final velocity = 0
Here, acceleration = - g(going upward) and g(coming downward)
Using the equations of motion:
• v = u + at
= > 0 = 49 + (-g)t
= > 49/9.8 = t
= > 5 = t
Total time taken to go and return = 2 * time taken to go
= > total time = 2*5 = 10 sec
• v² = u² + 2aS
= > 0² = 49² + 2(-g)S
= > 49²/2(9.8) = S
= > 122.5 m = S
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