Question

A ball is thrown vertically upwards with a velocity of 19.6 m/s. Calculate
a. The maximum height to which it rises.
b. The total time taken to return to the surface of the earth.

Answer 1

Answer:

Given that,

Initial velocity u=19.6m/s

Final velocity v=0

Time t=6sec

The acceleration is

We know that,

 v=u+at

0=19.6+a×6

a=−3.26m/s  

2

 

Now, the height is

From equation of motion

 s=ut+  

2

1

​  

at  

2

 

s=19.6×6−  

2

1

​  

×3.26×36

s=58.9

s=59m

Hence, the height of the tower is 59 m

Answer 2

Answer:

a) 19.6 m

b) 4s

Explanation:

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