a ball is thrown vertically upwards with a velocity of 20m/s. calculate the max. height attain by the ball
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here equation of motion is applied,s is distance
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maximum height attained by the ball is which is vertically thrown up is
H=u^2/2g
so, max height in this case is
H=20^2/2*10
H=400/20
H= 20 m.
Hope it helps you .
any doubt comment it .
H=u^2/2g
so, max height in this case is
H=20^2/2*10
H=400/20
H= 20 m.
Hope it helps you .
any doubt comment it .
bhargavi4527:
thank you
welcome
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