Question

a ball is thrown vertically upwards with a velocity of 40 m/s calculate
a) the maximum hight to which it rise
b) the total time taken to return to the surface of the earth​

Answer 1

Explanation:

a). v^2=u^2+2as

a=(-g)= (-10m/s^2)

v=0at the height max.

u=40

on solving

s = 80 m

b). total time = 2 × time taken to reach h max

= v=u+at

v=0 ,u=40 a= -10

on solving t = 4 second to reach height max,

time of whole flight = 8 seconds

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Answer 2

Answer:

u=40

v=o

g=-9.8

v^2-u^2=2gh

1600=2(-9.8)(h)

h=80 (approximately)

v=u+gt

0=40+(-9.8)(t)

-40=-9.8(t)

t=4sec( approximately)