A ball is thrown vertically upwards with a velocity of 40 m/s. Calculate the maximum height to which it rises?
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☆☆ AS-SALAMU-ALYKUM ☆☆
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GIVEN :-
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VELOCITY = 40m/s
REQUIRED :'
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MAXIMUM HEIGHT = ?
FORMULA FOR MAXIMUM HEIGHT IS
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Hmax = v^2 ÷ 2g
Hmax = 40 ^2 ÷ 2 × 10
Hmax = 40 × 40 ÷ 20
Hmax = 80 m
SO MAMINUM HEIGHT TO WHICH IT RISE IS 80m
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♡♤♤INSHALLAH MY ANSWER WILL PROVE HELPFUL ♡♤♡
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HAVE A NICE DAY☺☺
●●●●●●●●●●●●●●●●●●●●
GIVEN :-
▪▪▪▪▪
VELOCITY = 40m/s
REQUIRED :'
▪▪▪▪▪▪▪▪
MAXIMUM HEIGHT = ?
FORMULA FOR MAXIMUM HEIGHT IS
▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪
Hmax = v^2 ÷ 2g
Hmax = 40 ^2 ÷ 2 × 10
Hmax = 40 × 40 ÷ 20
Hmax = 80 m
SO MAMINUM HEIGHT TO WHICH IT RISE IS 80m
●●●●●●●●●●●●●●●●●●●●
♡♤♤INSHALLAH MY ANSWER WILL PROVE HELPFUL ♡♤♡
●●●●●●●●●●●●●●●●●●●●
HAVE A NICE DAY☺☺
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