woman shows an object of mass 500 gram with a speed of 25 metre per second if the object hits a wall and rebounds with half the original speed what is the change in momentum of the object
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Direction changes...after rebound ....be care full with sign of velocity see attachment
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Explanation:
m=500g=0.5kg
u=0m/s v=25m/s
(a) Impulse=m(v-u)
=0.5(25-0)
=12.5 Ns
(b) Velocity of the object when it rebounds back= -(v/2)= -25/2
= -12.5m/s
So, ∆P= 0.5(-12.5-25)
= -18.75 NS
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