A ball is thrown vertically upwards with a velocity of 49 metre per second calculate first the maximum height to which it Rises second the total time it takes to return to the surface of the earth
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Answer:
u=49 metre per second
V =0
g=9.8 metre per square
2gh=v^2×u^2
2*(-9.8)*h 24.01
h=122. 25 metr
v=u+gt
0 is equal to 249 -9.8t
t=5
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