A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate: (a) the maximum height to which it rises, (b) the total time it takes to return to the surface of the earth.
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u=49m/s.
v=0m/s.
g=-9.8m/s.
s=h= ?.
¡) from equation of motion.
2as= v square- u square.
2×(-9.8)×h=0 square- 49 square.
h= 112.8m.
¡¡) from equation of motion.
v=u+at.
t=v-u/a.
t=0-49/9.8.
=5s.
Total time taken by ball to reach back to the ground = 5+5 = 10s.
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