Math, asked by irshadali7088, 1 year ago

Ac is the diameter of the circle and is a diagonal of the quadrilateral abcd inscribed in it whose sides are ab = 30, bc = 40 units. Then the area ( in sq.Units) of that quadrilateral is

Answers

Answered by sashanksaimanikanta
0

Answer: 1089.88sq units.

Step-by-step explanation: ABCD is a quadrilateral inscribed in the circle with diameter AC. So, ΔABC and ΔADC are right angled triangles at ∠B=∠D=90°.

Now, area of ΔABC is given by

From Pythagoras theorem, we have

Again, in ΔACD

Therefore, area of ΔACD  is

.

Hence, the area of the quadrilateral ABCD is

sq units.

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