Ac is the diameter of the circle and is a diagonal of the quadrilateral abcd inscribed in it whose sides are ab = 30, bc = 40 units. Then the area ( in sq.Units) of that quadrilateral is
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Answer: 1089.88sq units.
Step-by-step explanation: ABCD is a quadrilateral inscribed in the circle with diameter AC. So, ΔABC and ΔADC are right angled triangles at ∠B=∠D=90°.
Now, area of ΔABC is given by
From Pythagoras theorem, we have
Again, in ΔACD
Therefore, area of ΔACD is
.
Hence, the area of the quadrilateral ABCD is
sq units.
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