Physics, asked by Pradnya786, 1 year ago

A ball is thrown vertically upwards with a velocity u with respect to ground from the balloon descending with velocity v. The ball will pass by the ball on after time

Answers

Answered by ajitgangwar
11
s=u′t−12gt2s=u′t−12gt2

0=(u+v)t−12gt20=(u+v)t−12gt2

t(t( (u+v)−12gt(u+v)−12gt )=0)=0

Since the required time cannot be 0,

(u+v)−12gt=0(u+v)−12gt=0

t=2(u+v)g

ajitgangwar: IIT jam physics qualified
ajitgangwar: ypp
ajitgangwar: you
ajitgangwar: nice to meet u
ajitgangwar: ok
ajitgangwar: any help..
Answered by junejaabhilasha
4

Answer:

Explanation:

s=u′t−12gt2s=u′t−12gt2

0=(u+v)t−12gt20=(u+v)t−12gt2

t(t( (u+v)−12gt(u+v)−12gt )=0)=0

Since the required time cannot be 0,

(u+v)−12gt=0(u+v)−12gt=0

t=2(u+v)g

Similar questions