A ball is thrown vertically upwards with an initial velocity of hundred metre per second find time taken to reach maximum height ,maximum height reached velocity at 5 seconds, velocity After 16 seconds (take G is equal to 10 metre per second square)
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it is very tipical question
after thinking ,maximum height reached velocity at 5 seconds, velocity After 16 seconds (take G is equal to 10 metre per second square)
the maximum height taken in time is 15meters seconds square
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Explanation:
u = 100m/s
maximum height reached = H = u²/2g = 100²/20 = 500 m.
velocity at 5 seconds = u - gt = 100 -50 = 50 m/s.( upward) ↑
u -10t = 0 , t = 10s
, velocity After 16 seconds = gt = 10x6 = 60 m/s. ( down ward)↓
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