Physics, asked by leaguegame990, 1 year ago

A ball is thrown vertically upwards with and velocity of 20 metre per second from the top of a multi storey building the height of the point where the ball is thrown is 25 metre from the ground how long will it be before the ball hits the ground at 1 G equals to 10 metre per second square

Answers

Answered by Sukhpreet85
2

(a)

H = u²/(2g)

H = 20²/(2×10)

H = 20 m

The ball will reach 20 m high from the point of projection.

It reaches 20 + 20.5 = 40.5m high from the ground.

(b)

t1 = 2u/g

t1 = 2×20/10

t1 = 4 seconds

If v is the velocity with which it hits the ground then,

v = √(u² + 2aS)

v = √(20² + 2×10×25)

v = 30 m/s

v = u + at

t2 = (v - u)/g

t2 = (30 - 20)/10

t2 = 1 second

Time taken for it to hit the ground = t1 + t2

= 4 + 1

= 5 seconds

Note: I took g = 10m/s².

Answered by sahildhande987
1

Explanation:

Please see the attachment

hope that helped

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