If 3 is one of the roots of the quadratic equation x^2-2kx+6=0
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Answered by
0
x= 3
put the value of x in eqn.
9 - 2(3)k + 6 = 0
9- 6k + 6 =0
3- 6k = 0
k = -3/-6
k= 1/2
put the value of x in eqn.
9 - 2(3)k + 6 = 0
9- 6k + 6 =0
3- 6k = 0
k = -3/-6
k= 1/2
joshuaJ:
hey buddy you made a mistake
Answered by
2
Hi here is your answer
ATQ
x=3
put the value of x in given equation
(3)^2-2×3×k+6=0
9-6k+6=0
15-6k=0
-6k=-15
k=15/6,5/2
ATQ
x=3
put the value of x in given equation
(3)^2-2×3×k+6=0
9-6k+6=0
15-6k=0
-6k=-15
k=15/6,5/2
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