A ball is thrown vertically upwards with speed 20 m/s. The time taken by it to reach half of the maximum height.
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u=20m/s
v=0
a=g= -10m/s2
using 1st eq of motion,
v=u+at
0=20+(-10t)
-20= -10t
t = 2sec
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Answer:
underroot 2h/h divided by 2
Explanation:
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