Question

A ball is thrown vertically upword with initial velocity of9.8meter per second it will reach the height of
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Answer 1

Answer:

GIVEN

V=0

g= -9.8

u=9.8

h=?

so, v²= u²+2gh

0²=(9.8)²+2*(-9.8)*h

0= 96.4-19.6*h

19.6*h = 96.4

h = 96.4/19.6

so,h= 4.918 ans.

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Answer 2

Answer:

Explanation:

Solution,

Here, we have

Initial velocity, u = 9.8 m/s

Final velocity, v = 0

Acceleration, a = g = - 9.8 m/s²

To Find,

Height reached , s = ?

According to the 3rd equation of motion,

We know that,

v² - u² = 2gs

So, putting all the values, we get

⇒ v² - u² = 2gs

⇒ (0)² - (9.8)² = 2 × (- 9.8) × s

⇒ 96.04 = - 19.6 s

⇒ 96.04/19.6 = s

⇒ s = 4.9 m.

Hence, the height reached by ball is 4.9 m.