Question

A ball is thrown vertically with intial velocity 30 m/s. What will be its position vector at time t=5 sec. Taking origin at the point of projection, vertical up as positive y-axis and horizontal as x-axis​

Answer 1

Answer:

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GIVEN :

initial velocity : 30m/s

final velocity : v

time : 5 seconds

Therefore by formula ,

$\tt{v = u + at }$

__v = 30 + 9.8×5

__v = 30 + 49

_v = 79 m/s

As it is thrown upwards it's 'g' is negative and therefore Answer is -79 j^

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