What is the moment of inertia of a rectangular plate about its diagonal?
Please provide derivation.
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The moment of inertia of the system about the diagonal of the square is N x 10. Four solid spheres each of diameter √5 cm and mass 0.5 kg are placed with their centres at the corners of a square of side 4 cm. The moment of inertia of the system about the diagonal of the square is N x 10-4 kg-m2, then N is.
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Explanation:
Statement: Find the moment of inertia of a rectangular plate of mass m, sides 2h and 2k , rotates about its diagonal.
I= Ʃmr^2
The Attempt at a Solution I=Ʃ m(x^2 +y^2) , let 2h parallel to x-axis, 2k parallel to y-axis. I= m(x cosθ)^2 + m (y cos ∅)^2 where angle θ is the angle between diagonal and x-axis.... But this is not parallel theorem case ....
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