Chemistry, asked by Amirdhavarshini930, 11 months ago

An alloy of copper and aluminum has 40% copper. Another alloy of copper and zinc has copper and zinc in the ratio 2: 7. These two alloys are mixed in ratio 5:3. Quantity of aluminum is what percent more/less than the quantity of copper in final alloy

Answers

Answered by aryanrajxxx751
0

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Answered by Anonymous
4

Answer:

between \: 32.25 \: and \: 40\%

Explanation

Answer:Between 32.25 and 40%.Explanation:For the first case the ratio of copper to alloy will be 2:3. Since, from the question we know that 40% of copper and 60% of aluminium is present. The separation will be 2x and 3x

Then, the ratio of copper to zinc is 2:7. So, the separation will be 2y and 7y. So, the total percentage of copper from the above deduction will be after putting x=7 and y=3. So, the copper will be 2*7 + 2*3=20. While the total is 35+27. So, the ratio will be 20/62*100= 32.25%.

Again, when the aluminium is maximum then putting x=1 and y=0. We will get the percentage of copper 2/5*100=40% . Hence, we see that the percentage of copper will lie between 32.25 and 40 percent.

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