A ball is thrown vertocally upwards from the ground it crossrs a point at the height of 25 m twice at an intergal of 4 second the ball was thrown with the velocity of
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A ball is thrown vertocally upwards from the ground it crossrs a point at the height of 25 m twice at an intergal of 4 second the ball was thrown with the velocity of
A ball is thrown vertocally upwards from the ground it crossrs a point at the height of 25 m twice at an intergal of 4 second the ball was thrown with the velocity of
aksh173:
oh sorry
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Explanation:
Answer:AT top
0 = u – at
0 = u -10*2
u = 20 m/s (t = 2s)
u becomes final velocity for the ground projection thus,
400 = u^2 – 2*-10*25
u = 30 m/s
This would be gthe velocity.
Explanation:
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