A ball is thrown with some initial velocity.an acceleration of g acts on it.find the distance travelled by it in the last second of upwards motion.
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See, u can use the equation of motion for S nth where n is the particular time.
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In the last second of the motion,
t = 1s
v = 0
a = -9.8 m/s
v = u +at
⇒ 0 = u + (-9.8)×1
⇒ u = 9.8 m/s
S = (v² - u²) /2a
= (0 - 9.8²) / 2×9.8
= 4.9 m
Distance travelled in last second of upward motion is 4.9m.
t = 1s
v = 0
a = -9.8 m/s
v = u +at
⇒ 0 = u + (-9.8)×1
⇒ u = 9.8 m/s
S = (v² - u²) /2a
= (0 - 9.8²) / 2×9.8
= 4.9 m
Distance travelled in last second of upward motion is 4.9m.
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