Question

A ball is trough vertically upward with an initially velocity of 49m/so. In how much time will the ball reach the maximum height? (g=98m/s2)​

Answer 1

Answer: 5 seconds.

Explanation:

Given in the attachment.

Answer 2

Explanation:

Initial velocity (u) = 49 m/s Final velocity (v) = 0 m/s

Gravity in toward down = + 9.8 m/s2 Gravity in toward up = - 9.8 m/s2

(i) We know, V2 - u2 = 2gs

or, (o)2- (49)2 = 2 X 9.8 X S

or, s = - (49)2/ 2 X 9.8 = 122.5 m

Maximum height = 122.5 m

(ii) We know, v = u + gt

or 0 = 49 +(- 9.8) X t

or 9.8 X t = 49

or, t = 49/ 9.8 = 5 s

If, time for upward direction = time for downward direction