Question

A ball launcher on the ground is aimed straight up , and it launches a baseball with an initial velocity of 49 m/s.The ball continues upward to a stop and then falls until caught by a player leaning out of a window 78.4 m above the ground .How long is the ball in the air before the player catches it ?

Answer 1

I think so the answer is 12005 meter it will cover the distance both up and down as.


U^2/2g =total distance covered


now divided speed with distance to get answer