Question

a ball moving here and there in a smooth circular cap is shown below. The points to which the ball goes on either side of lowest point B are 10 cm high from B. The speed of ball at B is?

Answer 1

Answer:

Mass = m

Gravitational acceleration = g = 10 m/s^2

Height = h = 10cm = 0.1 m ( 1m = 100cm )

Potential energy at Point B = mgh

= m * 10 * 0.1

= m

Therefore total energy at Point B is ‘m’ ( By Conservation of Energy , As here kinetic energy

is 0 )

At point C

the total energy is equal to Kinetic Energy ( By Conservation of Energy , As here potential

energy is 0 )

Kinetic energy = Total energy ( Total energy is always same every where )

1/2mv^2 = m

1/2v^2=1 ( subtracting m from both the side )

v^2 = 2

v = square root of 2

v = 1.4....m/s

Explanation: