Question

A ball moving with a velocity of 0.5 m/s. Its velocity is decreasing at the rate of 0.05 m/s2. What is its velocity after 5 s? How much time will it take from start to stop?

Answer 1

Explanation:

Given,

u = 0.5 m/s

a=0.05 m/s²

and v=0

Now, v = u − at

=> 0 = 0.5−(0.05×t)

=> t = 10 s

after 10s it will stop

velocity after 5s is

v = 0.5-(0.05×5) = 0.25 m/s

Answer 2

QUESTION :-

A ball moving with a velocity of 0.5 m/s. Its velocity is decreasing at the rate of 0.05 m/s2. What is its velocity after 5 s? How much time will it take from start to stop?

ANSWER :-

There is a ball which is moving with velocity = 0.5 m/s

the velocity starts decreasing at the rate of = 0.05 m/s^-2

To Find :-

a)- velocity after 5 s. (When t = 5 seconds)

b) - time it takes from start to stop. (When v = 0)

Given values-

Initial velocity ( u ) = 0.5 m/s

Final velocity ( v ) = 0

Retardation ( - a ) = - 0.05 m/s^-2

We know,

v = u + at

[ Newton's first equation of motion ]

a) -

Using Newton's first equation of motion equation -

v = 0.5 + ( - 0.05 ) × 5

v = 0.5 - 0.25

v = 0.25 m/s

b) -

Using Newton's first equation of motion equation -

0 = 0.5 - 0.05 × t

0-0.5 = -0.05 × t

-0.5 = -0.05 × t

0.5 ÷ 0.05 = t

50 ÷ 5 = t

10s = t

Hence,

Velocity after 5 seconds is 0.25 meter per second.

The ball stopped after 10 second from start.

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Thank you for the question !