A lady buys a dozen eggs, of which two turn out to be bad. She chose four eggs to scramble for breakfast. Find the chances that she chooses (a) all good eggs (b) three good and one bad eggs (c) two good and two bad eggs (d) at least one bad egg.
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a) probality = no.of favourable event / sample space
sample space = total no.of event
in A ) she needs all good eggs
sample space formula = no.of faces to the power no.of times
= 2 ( good and bad ) to the power 4
= 16
they are : ( let g be good and b be bad )
ggbb ggbg gggg gggb
bbgg bbgb bbbb bbbg
gbgb bgbg gbbb bggg
gbbg bggb and the other 2
probality = 1/16 as only 1 time gggg is coming
you can do the same method for b , c ,d
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