A ball of iron mass 1kg is dropped from tbe top of building the ball reaches the groind in 5s what is the velocity in m/s of the ball when it strikes the ground
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3
Answer:
we know that acts velocity is equal tov is equal to u + GT where is zero the value of g is and point 8 and the given time is 5 seconds so we should multiply 9.8 into 5 the final answer will be 49m/ s
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Answer:
Explanation:
Ball strike to the ground with 50 m/s
According to equation of motion
V=u+at
Acceleration is 10 =g
u=0
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