no of valence electrons in azide ion and how to calculate them?
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Nitrogen (the element) has 7 electrons. But two of those electrons are in the 1s orbital, and so are not considered valence. Therefore, a single elemental nitrogen has five valence electrons.
There are three nitrogens, and so 5×3=15 electrons for N3.
Finally, azide is N3−, there is an additional electron beyond the neutral form. So, the total number of valence electrons is 15+1=16.
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Answer:
Explanation:
16 valence electrons
N3^- = (5*3)+1 = 16
5 electrons of each nitrogen, as there r 3 nitrogen here= 5*3=15
+1 is the power on the ion
Therefore, there r total 16 valence electrons
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