Question

A ball of mass 0.1 kg moving with a speed of 40 metre per second strikes a bad and returns the opposite direction with the same speed the magnitude of the change in linear momentum will be

Answer 1

Answer:

8 kg-m/s

Explanation:

∆p=p2-p1

∆p=(40×0.1)-(-40×0.1)

∆p=8kg-m/s

Answer 2

Answer:

hello guys here is your answer

Explanation:

we know that

p=mv

change in momentum is = p2-p1

so : (40*0.1)-(-40*0.1)

this gives ans as 8kg m/s

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