A ball of mass 0.2 kg is thrown against the wall . the ball strikes the wall normally with velocity of 30m/sand rebounds with velocity of 20m/s. calculate the impulse of the force exerted by the ball on the wall
Answers
Answered by
0
Given that,
mass, m=0.2kg
initial velocity, u=30m/s
final velocity, v=20m/s
impulse, I=m (v-u)
=0.2(20-30)=0.2×(-10)= -2 N/s
mass, m=0.2kg
initial velocity, u=30m/s
final velocity, v=20m/s
impulse, I=m (v-u)
=0.2(20-30)=0.2×(-10)= -2 N/s
Answered by
0
Answer:
Impulse = m (-20 – 30) = -5Ns
Explanation:
Similar questions