Physics, asked by pingspoofer, 1 year ago

A ball of mass 0.2 kg is thrown vertically upwards with an initial velocity of 20 m/s. Calculate the maximum potential energy it gains as it goes up.

Answers

Answered by poonamrana992
11

P.E.=mgh

P.E.=0.2x20x9.8

P.E.=39.2J


pingspoofer: g is not given. Will it be fine if we assume it in an examination?
poonamrana992: g if not given should always be taken as 9.8
Answered by AryaVyas
14

s = ut +  \frac{1}{2} a {t}^{2}  \\ s = 20 \times 2  -  \:  \:  \frac{1}{2}  \times 10 \times 4 \\ s = 20 \: m
p \: energy \:  = mgs \\  =  \frac{2}{10}  \times 10 \times 20 \\  = 40 \: \: joule

pingspoofer: I'm curious as to what you assumed as 't' here. Thanks!
AryaVyas: Time and I got time from 1st equation of motion V = u + at
AryaVyas: Please mark as Brainliest if useful
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