A ball of mass 0.2 kilogram is dropped from a height of 1 metre above the ground if it rebounds to a height of 0.6 find the coefficient of restitution between the surface of the ball and ground
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Answer:
coefficient of restitution is 0.6
Explanation:
When a ball is dropped from a height on a ground surface which has mass larger than mass of the ball, then the resulting impact is considered as the an impact with infinite mass. Due to impact, there is loss of kinetic energy and the law of conservation of momentum is not applicable.
Height (H) after n bounce after falling from height h is given as
e= coefficient of restitution
H=(e^n)xh
H = 0.6 ( height after first rebound)
h= 1m; (original height)
n=1
Substituting the given values;
e= 0.6/1
e= 0.6
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