Question

A ball of mass 0.20kg is thrown vertically upwards with an initial velocity of 20m/s.calculate the maximum potential energy it gain as it goes up.

Answer 1

${\mathcal{\red{\underline{\huge{ANSWER}}}}}$

$<b>As we know that it$
will have the maximum potential energy at H max

then H max $\frac{u^2}{2g}$

= $\frac{20^2}{2×10}$

= $\frac{400}{20}$

= 20m

now as PE = mass × g × height

=> 0.2 × 10 × 20
=> 40 Joles

Answer 2

maximum potential energy = 40 J

a particle is thrown vertically upwards with speed 20 m/s. at maximum height it velocity becomes zero so, the kinetic energy becomes zero but potential energy becomes maximum at that point.

from law of conservation of energy,

initial mechanical energy = final mechanical energy

⇒initial kinetic energy + initial potential energy = final kinetic energy + final potential energy

⇒1/2 mv² + 0 = 0 + final potential energy

⇒1/2 × 0.2kg × (20 m/s)² = final potential energy

⇒final potential energy = 1/2 × 0.2 × 400 = 40J

and final potential energy is the maximum potential energy so, maximum potential energy = 40 J

also read similar questions: A ball is thrown vertically upwards with a velocity of 49m/s.calculate the speed at 2.5 seconds

https://brainly.in/question/12591985

A body of mass 2 kg is thrown vertically upwards with an initial velocity of 20m/s. What will be its potential energy at...

https://brainly.in/question/1823406