A ball of mass 0.2kg falls through air with an acceleration of 6m/s^2. calculate the air drag on the ball
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Answer:F1=ma
F=0.2×6
1.2N(it's the force by which ball is coming down)
F2=ma
F=0.2×9.8
1.96N(the force apposing the ball)
Now drag will be
F2 - F1
1.96N-1.2N =.76N
Explanation:
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